A dealer is asked for a two-way quote on a cash-settled call while the stock trades at 99 bid and 101 ask. Without trading costs one replicating portfolio would fix a single price, but now buying the hedge, selling it later and covering a short position all happen at different prices. The dealer needs the lowest price at which selling the call can be hedged without risk, and the highest price at which buying it can be hedged the same way. This lesson computes both bounds in a one-period model, shows that they bracket the frictionless price, and checks with shadow prices that no price between them creates an arbitrage.
Key terms
Bid-ask spread
Definition At each date the stock can be bought at the ask price and sold at the bid price , where . The bid-ask spread is , and the mid-price is . On this page the cash account has no friction. It starts at and borrows and lends at the same growth factor per period, so . A position of shares bought and sold again at once loses . With a spread the cash flow of a trade depends on its direction, so a portfolio no longer has one value that is linear in its holdings, and the self-financing condition must use the cash actually paid or received.
In plain words Buying costs the higher price and selling brings in the lower one. The mid-price says neither what a purchase costs nor what a sale brings in.
Example In the constructed example of this lesson the mid-price is 100 today, with bid 99 and ask 101, a spread of 2. Buying one share and selling it straight back loses 2 even though the mid-price has not moved. At the end of the period the mid-price is 80 or 120, with bid 79.2 and ask 80.8 in the first state and bid 118.8 and ask 121.2 in the second. The cash account grows by the factor over the period.
Proportional transaction costs
Definition In a model with proportional transaction costs there is a mid-price process and a constant with , and
The value is the frictionless market. Write and . Changing a stock holding by shares at date costs the cash
and liquidating a holding at date , by selling a long holding at the bid or buying back a short holding at the ask, brings in
The trading cost is convex in , the liquidation value is concave in , and both are multiplied by when the position is multiplied by a number . In the one-period model of this page a portfolio buys shares at date 0, a short sale when , and holds in the cash account, a debt when . Its initial cost is
and at date 1 it brings in in terminal state , where is the liquidation value at the prices of that state.
In plain words Each share traded costs an extra fraction of the mid-price, whichever way it is traded. A purchase and a sale of the same size cancel in shares but not in cash, and closing a long position and closing a short position use opposite sides of the market.
Example With , buying shares today costs , which the formula writes as . Selling them at the end of the period brings in or . A short sale of shares brings in today, and buying the shares back costs or .
Covering hedge
Definition Let a claim pay the cash amount in terminal state . A covering hedge of is a portfolio whose liquidation cash at maturity covers the claim, so that
in every terminal state . A seller of needs a covering hedge of . A buyer of who wants to lock in the purchase needs a covering hedge of the negative claim , which pays , because the claim together with that hedge leaves a nonnegative amount in every state. A covering hedge that holds with equality in every state replicates the claim after costs. Long holdings are valued at the terminal bid and short holdings at the terminal ask, so a hedge computed from mid-prices is in general not a covering hedge.
In plain words A covering hedge is a position in stock and cash that, once closed at the prices actually available, leaves enough cash to pay what is owed whatever happens.
Example The claim is a call on the mid-price with strike 100, settled in cash, so in the states with mid-price 80 and 120. To cover it with a long position, match the claim at the terminal bids. The holding is shares, whose sale brings in 40 or 60, so a debt of 40 at maturity, which is a loan of today, leaves 0 and 20. To cover , sell short shares and put in the cash account. Buying the shares back costs 40 or 60 and the cash pays 40, which leaves 0 and . Both hedges cover their claims exactly. With the frictionless hedge ratio and the same cash amounts, neither position covers its claim, as the second question below shows for the seller.
Superreplication
Definition Superreplication means covering a claim at the lowest possible initial cost. The superreplication price of is
where the inequality must hold in every terminal state. For a fixed holding the cheapest cash position is , so is the infimum over of
In this one-period model is convex and piecewise linear, so a point where its slope changes from negative to positive is a minimum. Matching the claim in every state gives a covering hedge, and this slope check shows whether it is the cheapest one. A consistent price system that values the claim at the hedge’s cost, as in the last card, is another certificate of optimality. With and a claim that can be replicated, the superreplication price in a market without arbitrage is the replication price.
In plain words Among all stock and cash positions that keep the seller safe, find the cheapest. Its cost is the least amount of money from which the claim can be paid in every state.
Example Take the call with . For the shares are sold at the bids, so the cash at maturity must be at least in the down state and in the up state. For the up state binds, the cost is , and its slope is . For the down state binds and the slope is . For the shares are bought back at the asks, the up state binds, and the slope is , so going short only raises the cost. The minimum is at ,
which is above the frictionless replication price , obtained from the hedge ratio 0.5 and the same loan .
Seller and buyer price bounds
Definition The seller price bound of a claim is , and the buyer price bound is
the largest price a buyer can pay for and still cover the position. Three facts follow from the definitions. If the claim can be sold at a price , selling it and buying a covering hedge that costs less than leaves positive cash today and a nonnegative amount in every state at maturity, an arbitrage. If the claim can be bought at , buying it and setting up a covering hedge of is an arbitrage in the same way. If the stock and cash market has no arbitrage, then . Otherwise hedges of and of could be found whose total cost is negative, and combining positions never raises the trading cost and never lowers the liquidation cash, so the combined position would cost less than zero and bring in at least in every state, which is an arbitrage. The bounds come from covering arguments only, and prices between them cannot be excluded by those arguments. When , the market has no arbitrage and can be replicated, both bounds equal the replication price.
In plain words The seller bound is the cheapest safe way to deliver the claim, and the buyer bound is the most a buyer can pay and still be safe. Outside the interval someone can lock in a riskless profit. The width of the interval comes from the trading sides of the hedges, not from an error margin attached to a mid-price value.
Example For the call with , the buyer bound is the short-sale proceeds minus the cash set aside, which is . The interval runs from to , a width of about . It contains the frictionless price , which is not its midpoint . For hedges of the same form stay optimal, and
The interval widens as the spread grows, to about and at , and both bounds tend to as . For the stock no longer helps the seller, whose bound becomes , the cost of holding 20 in cash.
Shadow price
Definition A shadow price is a process with
at every date and in every state, together with a probability measure that gives every state positive probability and makes a -martingale. The pair is called a consistent price system. In one period with growth factor the martingale condition reads . If a consistent price system exists, the bid-ask market has no arbitrage. To see this, compare each trade with a frictionless market at the shadow price. Purchases cost at least the shadow price and sales bring in at most the shadow price, so and in every state, hence
A portfolio with whose liquidation cash is nonnegative in every state therefore has liquidation cash zero in every state, because gives every state positive probability. The same chain shows that every covering hedge of costs at least . So every claim value from a consistent price system lies between and , and trading the claim at such a value adds no arbitrage. The converse, that no arbitrage produces a consistent price system, is not proved here, and the stronger notion that asks for shadow prices strictly inside the spread belongs to the dynamic theory of transaction costs, which is outside this lesson.
In plain words A shadow price is a frictionless price path that stays inside the spread at every node and has a pricing measure. Real trades are never better than trades at the shadow price, so an arbitrage in the real market would also be an arbitrage in the shadow market, which has none.
Example The seller bound of the call comes from the shadow price equal to the ask 101 today and to the bids 79.2 and 118.8 at maturity, with up probability
and claim value . The buyer bound comes from the bid 99 today and the asks 80.8 and 121.2 at maturity, with up probability and claim value . Both probabilities lie strictly between 0 and 1, so both are consistent price systems even though their shadow prices sit on the edges of the spread. Unlike the open interval of the frictionless incomplete market in Market completeness and nonunique prices, the endpoints here can be quoted without creating an arbitrage. For a weight with , mix the two systems state by state,
where and are the probabilities of terminal state in the two systems, and set . Each is a weighted average of two prices in the same spread, the martingale condition holds because it holds for both systems, and the claim value is . So every price in the closed interval comes from a consistent price system. Mixing the probabilities and the shadow prices with unrelated weights would in general break the martingale condition. At the shadow price today is 100, the up probability is about , and the claim value is about .
Check yourself
- In the same model with , a put on the mid-price with strike 100, settled in cash, pays 20 in the state with mid-price 80 and 0 in the state with mid-price 120. Find its seller and buyer price bounds and the hedges that attain them.
Show the answer
The seller covers , which falls as the stock rises, with a short position of shares bought back at the asks and cash . Matching both states gives and , so and . The short sale brings in today, so
The buyer covers with a long position of shares sold at the bids for 40 or 60 and a loan of , which needs 60 at maturity. That hedge costs , so the buyer bound is . The same slope check as for the call shows that both hedges are the cheapest. The interval contains the frictionless put price .
- A classmate hedges the sold call with the frictionless hedge, shares bought at the ask and a loan of . Show that this portfolio does not cover the call, find the cheapest covering hedge that keeps shares, and compare its cost with the seller bound.
Show the answer
At maturity the shares are sold at the bids for or , and the loan requires 40, which leaves in the down state and in the up state, short of the claim by and . With shares the cash at maturity must be at least , so the loan can be at most . The cost is
which exceeds the seller bound by about . That difference is the size of the slope of the cost function below times the shortfall in the holding, which gives . The frictionless hedge ignores that shares are sold at the bid, so it either fails to cover or costs more than needed.
- A dealer offers to buy the call from you at 13.20. Construct an arbitrage. Then explain why a bid of 12.50 cannot be exploited this way, and give a consistent price system that shows no strategy exploits it.
Show the answer
Sell the call to the dealer for 13.20, buy shares at 101 and borrow . This costs , so about is left today. At maturity the shares are sold at the bids for 40 or 60, the loan takes 40, and the call takes 0 or 20, which leaves exactly 0 in both states. Putting the in the cash account turns this into a sure gain of about at maturity from a position that cost nothing.
A bid of 12.50 is below the seller bound, so selling the call does not pay for any covering hedge. To show that no strategy works, take the up probability , which values the call at 12.50, with shadow prices equal to the bids 79.2 and 118.8 at maturity. The martingale condition gives the shadow price today
which lies between the bid 99 and the ask 101. Both state probabilities are positive, so this is a consistent price system that also prices the call at the dealer’s bid, and by the shadow price argument no combination of selling calls at 12.50 and trading the stock and cash is an arbitrage.